# Solve quadratic equation by factoring

How to solve this quadratic equation $x^2-4x-5=0$ by factoring?

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\begin{align} x^2-4x-5 &=0 \\ (x-5)(x+1) &=0 \\ x-5=0 \ \ &\ \text{or} \ \ x+1=0 \\ x=5 \ \ &\ \text{or} \ \ x=-1 \end{align}
Answer: $x=5 \ \ \text{or} \ \ x=-1$.

Last time edited 2019-01-19

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