If we have quadratic equation [tex]ax^2+bx+c=0[/tex], then the discriminant of the quadratic equation is the number D and it is found by formula: $$\displaystyle D=b^2-4ac$$ Then the solutions [tex](x_1 \ \text{and} \ x_2)[/tex] of the quadratic equation we will find with this formula: $$\displaystyle x_{1,2}=\frac{-b \pm \sqrt{D}}{2a}$$ **Number of solutions**

If [tex]D > 0[/tex], then the quadratic equation thus has two distinct real solutions. If [tex]D = 0[/tex], then the quadratic equation has one real solution. If [tex]D < 0[/tex], then the quadratic equation has no real solutions.

Last time edited 2019-01-19

Algebraviews 69answers 0activity 2 mo