Find the equation of the line that passes though the points (-2,5) and (8,15)?

Algebraviews 689answers 1activity 5 mo
General equation of the straight line function is [tex]y=mx+c[/tex], where m is slope. $$m=\frac{y_2-y_1}{x_2-x_1}=\frac{15-5}{8-(-2)}=\frac{10}{10}=1$$ If [tex]m = 1[/tex], then we have [tex]y=x+c[/tex]. Now we can easy find c by inserting one of the given points coordinates to our equation. $$15= 8 + c, \ \ c=7$$ Answer: [tex]y=x+7[/tex]

Last time edited 2019-01-18